Is roulette actually rng tho?

[Tauntshaman]

Gambling is a risk vs reward situation. Its all about if its worth the risk.
if risk>reward you shouldn't gamble
if risk=reward you [i[shouldn't[i/] gamble
if risk<reward you should gamble
With virtual money this is how i gamble, I try to find low risk high reward gambles. However it is almost never so clear cut so if you are winning quit while you ahead and if find yourself close to winning again and again...stop before you sink more and more money in, if you think you can win you will keep spending money, that is mainly with slots but it can be applied to other gambling games as well

problem is it seems very fair. if there is only 2 shots, then it's fair game, and the game makes sure that the 2 ppl bets the same.
i tries to make money by playing multi ppl roulette games and i managed to earn a total like 400pts, and i lost 1110 in this single game

[Marshmallow Marshall]

Superstition of mine, but I coulda sworn the first pull shoots far less than it should - the game felt weighted to the last few pulls.

p;edit in general when programming languages include an "rng function", the "rng function" does NOT seem balanced XD

Of course.

Suppose a game of Russian Roulette with 8 slots.

1st shot: 1/8 chance of getting bullet.
2nd shot: 1/7 chance of getting bullet, because 8 slots - 1 because of first shot = 7 slots.
3rd shot: 1/6 chance of getting bullet, because 8 slots - 2 because of two first shots = 6 slots.
And so on.


The nerd maths Helz didn't want to get into are basically something about the first shots getting together, to come to a probability that is rather high, which explains Hybrid's strategies.

[Hybrid]

Instead of whing about it like them just risk it like me
I ve gained 10 15 k ish points from roulettes lol

[Magoroth]

Sounds like you were just unlucky. You've got to 'feel' the right time to pull in order to win roulette - I'm not being sarcastic or edgy, this is something I've noticed and it is actually true.

[Tauntshaman]

Of course.

Suppose a game of Russian Roulette with 8 slots.

1st shot: 1/8 chance of getting bullet.
2nd shot: 1/7 chance of getting bullet, because 8 slots - 1 because of first shot = 7 slots.
3rd shot: 1/6 chance of getting bullet, because 8 slots - 2 because of two first shots = 6 slots.
And so on.


The nerd maths Helz didn't want to get into are basically something about the first shots getting together, to come to a probability that is rather high, which explains Hybrid's strategies.

not true.

Suppose a game of Russian Roulette with 8 slots.

if one is the THIRD TO SHOOT (instead of third shot): 1/8 chance of getting bullet
chance of the bullet not in the first 2=6/8
chance of getting hit=1/6
chance of dying as the third guy=1/6*6/8=1/8

It is all fair until second round comes.

[Tauntshaman]

Sounds like you were just unlucky. You've got to 'feel' the right time to pull in order to win roulette - I'm not being sarcastic or edgy, this is something I've noticed and it is actually true.

survivorship bias

[Tauntshaman]

lol initially i posted this to discuss the code, and it turns out to be al about probablility

[Marshmallow Marshall]

Instead of whing about it like them just risk it like me
I ve gained 10 15 k ish points from roulettes lol

Then you're lucky lol

[Marshmallow Marshall]

lol initially i posted this to discuss the code, and it turns out to be al about probablility

There's no code problem though. That's why it's all about probabilities.

[yzb25]

Of course.

Suppose a game of Russian Roulette with 8 slots.

1st shot: 1/8 chance of getting bullet.
2nd shot: 1/7 chance of getting bullet, because 8 slots - 1 because of first shot = 7 slots.
3rd shot: 1/6 chance of getting bullet, because 8 slots - 2 because of two first shots = 6 slots.
And so on.


The nerd maths Helz didn't want to get into are basically something about the first shots getting together, to come to a probability that is rather high, which explains Hybrid's strategies.

I'm not sure the way you're thinking about the probability is correct. If you add all the possibilities together, you should get 1.

But 1/8+1/7+1/6+1/5+1/4+1/3+1/2+1=/=1.

1/8+1/7+1/6+1/5+1/4+1/3+1/2=/=1 either.

[OzyWho]

I'm not sure the way you're thinking about the probability is correct. If you add all the possibilities together, you should get 1.

But 1/8+1/7+1/6+1/5+1/4+1/3+1/2+1=/=1.

1/8+1/7+1/6+1/5+1/4+1/3+1/2=/=1 either.

In a N chamber roulette, the Nth shot will always be 100% (or "1", as you call it)

[yzb25]

In a N chamber roulette, the Nth shot will always be 100% (or "1", as you call it)

When you've reached the N'th shot, the odds are 100%, yes. But at the start of the game before you know whether or not you'll reach the N'th shot, the probability that the Nth shot is chosen is not 100%. That would mean that in every game that's played the game goes to the last shot.

[OzyWho]

When you've reached the N'th shot, the odds are 100%, yes. But at the start of the game before you know whether or not you'll reach the N'th shot, the probability that the Nth shot is chosen is not 100%. That would mean that in every game that's played the game goes to the last shot.

Ohhh true. I never realized he wanted calculate the odds of getting to each shot.

[OzyWho]

the odds of getting to each shot.

Isn't it 1/8th for each?
Meaning it doesn't matter which player slot you are as long as you can divide chamber count with player count and each player has the same amount of possible shots...

[Tauntshaman]

Isn't it 1/8th for each?
Meaning it doesn't matter which player slot you are as long as you can divide chamber count with player count and each player has the same amount of possible shots...

Right. So it's all fair game if there is n ppl with n shots. but if there are 6 shots with 4 ppl, then it becomes super unfair for the first 2 to go

[Marshmallow Marshall]

I'm not sure the way you're thinking about the probability is correct. If you add all the possibilities together, you should get 1.

But 1/8+1/7+1/6+1/5+1/4+1/3+1/2+1=/=1.

1/8+1/7+1/6+1/5+1/4+1/3+1/2=/=1 either.

Mhmmm that's true. But there's another thing that makes you lie, and I forgot to put it: gun jamming. 1% gun jamming.

[Arsonist]

The roulette is basically rng only on choice of 1st player i guess.
I knew it always.

The system:

Let the roulette start with the 10 shots.

Shot 1: 1/10 chanice to die
Shot 2: 1/9 chanice to die
Shot 3: 1/8 chanice to die
...
Shot 8: 1/3 chanice to die
Shot 9: 1/2 chanice to die
Shot 10: Loses the game.

Also it depend on the pull count of a 1 player.

6th pull in a row - die.

The rewards calculation:

It depends on the bet and number of pulls in a row.

Pull-depend:

Pulled twice +25% to reward
Pulled 3 times, +33% to reward
Pulled 4 times, +66% to reward
Pulled 5 times, +75 to reward
Pulled 6 times, die.

Bet-depend:

Player 1 bets 10 points
Player 2 bets 15 points
Player 3 bets 100 points

Player 3 loses roulette.

15 > 10 on 50%
50:2=25

So, the player 2 gets the 25% more pts, than player 1
So, player 1 gets 25 pts and player 2 gets 75 pts.

Maximum bet:

Maximum bet is the square root of all your points.

But:
a+b+c ≥ d
When a, b, c is the other's players bet and d is your bet.

That's basically how the mechanics of roulette works.
Hopefully i helped you with that question.
Respond this message with a quote if i'm incorrect.

[Tauntshaman]

That's basically how the mechanics of roulette works.
Hopefully i helped you with that question.
Respond this message with a quote if i'm incorrect.[/COLOR][/FONT]

no. we are not talking about the basic -roulette, we are talking about -roulette a b

plus your thing is wrong. if p1 bet 10 and p2 bet 15, then then should get 40:60 on p3 death.

[Unknown1234]

All this can be avoided by just doing 2-person roulette, or no roulette. Simple as that.

[Arsonist]

no. we are not talking about the basic -roulette, we are talking about -roulette a b

plus your thing is wrong. if p1 bet 10 and p2 bet 15, then then should get 40:60 on p3 death.

Nah, i don't played the game.