A New Random Thinker # 11

[kyle1234513]

A mother has three sick children. She has a 24-ounce bottle of medicine and needs to give each child eight ounces of the medicine. She is unable to get to the store and has only three clean containers, which measure 5, 11 and 13 ounces. The electricity is out and she has no way of heating water to wash the containers and doesn't want to spread germs. How can she divide the medicine to give each child an equal portion without having any two children drink from the same container?


huehuehue math....

Glip got it right!

Answer - Multiple answers can be obtained.

Glip's - Fill the 13 oz cup. Use the now-full 13 oz cup to fill the 5 oz cup. Put the remainder from the 13 oz cup into the 11 oz cup. Give 11 oz cup to child A to drink. Pour contents of 5 oz cup back into 13 oz cup. Refill 13 oz cup. Use 13 oz cup to fill 5 oz cup again. Give 13 oz cup to child B to drink, give 5 oz cup to child C. Refill child's C cup with the remaining 3 oz of medicine after child C drinks the first 5

Mine - Fill the 5 oz and 11 oz Containers from the 24 oz container. This leaves 8 oz in the 24 oz bottle. Next empty the 11 oz bottle by pouring the contents into the 13 oz bottle. Fill the 13 oz bottle from the 5 oz container (with 2 oz.) and put the remaining 3 oz in the 11 oz bottle. This leaves the 5 oz. container empty. Now pour 5 oz from the 13 oz bottle into the 5 oz bottle leaving 8 oz in the 13 oz bottle. Finally pour the 5 oz bottle contents into the 11 oz bottle giving 8 oz in this container.

[Glip]

A mother has three sick children. She has a 24-ounce bottle of medicine and needs to give each child eight ounces of the medicine. She is unable to get to the store and has only three clean containers, which measure 5, 11 and 13 ounces. The electricity is out and she has no way of heating water to wash the containers and doesn't want to spread germs. How can she divide the medicine to give each child an equal portion without having any two children drink from the same container?


huehuehue math....

Fill the 13 oz cup. Use the now-full 13 oz cup to fill the 5 oz cup. Put the remainder from the 13 oz cup into the 11 oz cup. Give 11 oz cup to child A to drink. Pour contents of 5 oz cup back into 13 oz cup. Refill 13 oz cup. Use 13 oz cup to fill 5 oz cup again. Give 13 oz cup to child B to drink, give 5 oz cup to child C. Refill child's C cup with the remaining 3 oz of medicine after child C drinks the first 5.

[AppleyNO]

Fill the 13 oz cup. Use the now-full 13 oz cup to fill the 5 oz cup. Put the remainder from the 13 oz cup into the 11 oz cup. Give 11 oz cup to child A to drink. Pour contents of 5 oz cup back into 13 oz cup. Refill 13 oz cup. Use 13 oz cup to fill 5 oz cup again. Give 13 oz cup to child B to drink, give 5 oz cup to child C. Refill child's C cup with the remaining 3 oz of medicine after child C drinks the first 5.
GG

or you could just let them die.

[kyle1234513]

Fill the 13 oz cup. Use the now-full 13 oz cup to fill the 5 oz cup. Put the remainder from the 13 oz cup into the 11 oz cup. Give 11 oz cup to child A to drink. Pour contents of 5 oz cup back into 13 oz cup. Refill 13 oz cup. Use 13 oz cup to fill 5 oz cup again. Give 13 oz cup to child B to drink, give 5 oz cup to child C. Refill child's C cup with the remaining 3 oz of medicine after child C drinks the first 5.

I've done it differently using the original container, but this math checks out. Since the only rule was no child could drink from a container that another child had taken the medicine from, multiple answers can be derived. This answer is acceptable.

[Glip]

Alternatively:

Fill 11 oz cup. Use 11 oz cup to fill 13 oz cup. Fill 5 oz cup. Use 5 oz cup to top off 13 oz cup. Pour remainder from 5 oz cup into 11 oz cup. Use 13 oz cup to fill 5 oz cup. Pour contents of 5 oz cup into 11 oz cup. Give 11 oz cup to child A, 13 oz cup to child B, and the bottle to child C. ( or fill and refill the 5 oz cup, if you don't want kids drinking from the bottle even if they're drinking the last of it ^.^)